public String censorString(String originalString)
{
StringBuffer orig = new StringBuffer(originalString);
Pattern p = Pattern.compile("[0-9/A-Z/a-z]+");
Matcher m = p.matcher(orig);
StringBuffer censor = new StringBuffer();
boolean result = m.find();
while (result)
{
String match = originalString.substring(m.start(), m.end());
if(match.equals("badword"))
m.appendReplacement(censor, "[censored]");
result = m.find();
}
m.appendTail(censor);
return censor.toString();
}
Function To Censor String
Here is a function that censors a string, but leaves in all of the punctuation. It searches for strings of letters and numbers and if it matches "badword", will replace it with "[censored]".
find similar posts:
Java,
Patterns,
Regular Expressions
Subscribe to:
Post Comments (Atom)
apt quotation..
“A man should be able to change a diaper, plan an invasion, butcher a hog, conn a ship, design a building, write a sonnet, balance accounts, build a wall, set a bone, comfort the dying, take orders, give orders, cooperate, act alone, solve equations, analyze a new problem, pitch manure, program a computer, cook a tasty meal, fight efficiently, die gallantly. Specialization is for insects.” by Robert A. Heinlein (author, aeronautical engineer, and naval officer)
No comments:
Post a Comment